How many distinct permutations start with the letter m of the word ambulance?

Module OverviewModule OverviewLearning Module 02ProbabilityKnowledge Area Code:BSEECourse Code:ENDA0213Learning Module Code:LM- ENDA0213LM02-ENDA0213

Learning Module: Engineering Data Analysis53Module OverviewIntroductionOn this module and the succeeding modules, we will focus on inferential statistics in which wewill make a conclusion on the population based on the data set. This module will discuss theon how to compute for the probability of an event using a priori approach.Topic 01:Counting TechniquesTopic 02: Basic ProbabilityLearning OutcomeDiscuss the basic concepts of probability and counting techniques.Minimum Technical Skills RequirementProblem Solving and Computation SkillsLearning Management SystemSchoology Access Code:ENDA0213-EE2A: QSV6-P9WP-9RH78ENDA0213-EE2B: M43V-ZVWK-MPD77ENDA0213-EE2C: GMRR-777V-3KT9XDurationTopic 01:Counting Techniques=6 hoursTopic 02: Basic Probability=6 hoursDelivery ModeOnline (synchronous or asynchronous)Module Requirement with RubricsThe following criteria and the corresponding points shall be used to assess every wordedproblem in the quizzes, exercise and term exam.CriteriaDescriptionPointsUnderstandingAble to translate the thought of the problem into visualdrawing that signifies that the student has read andunderstand the problem.5 pointsInterpretationAble to establish what is asked in the problem and theappropriate mathematical equation/formula to be used tosolve the problem.5 pointsExecutionAble to solve the problem using appropriatemathematical strategies and have arrived at the correctanswer15 pointsTOTAL25 points

LM02-ENDA0213CoursePacket01Learning Module 02ProbabilityCourse Packet 01Counting TechniquesKnowledge Area Code:BSEECourse Code:ENDA0223Learning Module Code:LM- ENDA0213Course Packet Code:LM02-ENDA0213-01

Learning Module: Engineering Data Analysis55Course Packet 01LM02-ENDA0213CoursePacket01Course Packet 01Counting TechniquesIntroductionUnderstanding the concept of probability deals with the uncertainty brought by giving concludingstatement about a population where only a part of it is being tested. Probability provides numericaldescription on how certain we are of outcome of a particular experiment. One way to determine theprobability of an outcome is using the a priori approach in which all the outcomes of the experiment hasthe same probability of occurrence. The number of outcomes can be counted manually, however, in anexperiment where there are numerous possible outcomes, counting manually may be difficult and time -consuming. Thus, we need counting techniques to do this.ObjectivesTo understand and use the terminology of counting techniques.To calculate counting techniques using Addition Rules and Multiplication Rules.

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Suppose that, out of #n# things, #r_1# are of first type, #r_2# are of

second type, #r_3# are of third type,..., where #r_1+r_2+r_3+...=n.#

Then, no. of possible distinct permutations is given by

#(n!)/{(r_1!)(r_2!)(r_3!)...}#

In our Example, there are total #8# letters in the word INFINITY ,

out of which, #3# letters are of one type (i.e., the letter I ), #2#

are of second type (i.e., the letter N ) and the remaining #3# are

(i.e., the letters F,T and Y) are each of #1# type.

Thus, #n=8, r_1=3, r_2=2, r_3=r_4=r_5=1#.

#"The Reqd. No. of Permutations="(8!)/{(3!)(2!)(1!)(1!)(1!)}#

#=(8xx7xx6xx5xx4)/(2!)=3360.#

Enjoy Maths.!

How many distinct permutations can be made from the letters of the word medical?

Hence, the answer is 720.

How many distinct permutations are there?

Starting from a set of n objects in some reference order (e.g., the number sequence 1, 2, 3, …, n), we can make a permutation of them to some other order; the total number of distinct permutations that are possible is n! (choose the first object n ways, then choose the second in n − 1 ways, etc.).

What is a distinct permutation?

A permutation of a set of distinct objects is. an arrangement of the objects in a specific order without repetition.